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Math Help - gradient operator

  1. #1
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    gradient operator

    Am really not sure how to prove this question, does



     \nabla . (\frac{1}{r}r) =  \frac{\partial}{\partial x} + \frac{\partial}{\partial y} + \frac{\partial}{\partial z} \dot     (\frac{1}{x^{2}+y^{2}+z^{2})^{1/2} ( x+y+z) [/tex]
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  2. #2
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    Re: gradient operator

    $\dfrac {\vec{r}} {\| \vec{r} \|} = \left\{ \dfrac {x} {\sqrt{x^2+y^2+z^2}},\dfrac {y} {\sqrt{x^2+y^2+z^2}},\dfrac {z} {\sqrt{x^2+y^2+z^2}} \right \}$

    Take the divergence and then take the gradient and plow through the algebra. It's not that bad. You end up with the right hand side when you're done.
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  3. #3
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    Re: gradient operator

    Quote Originally Posted by romsek View Post
    $\dfrac {\vec{r}} {\| \vec{r} \|} = \left\{ \dfrac {x} {\sqrt{x^2+y^2+z^2}},\dfrac {y} {\sqrt{x^2+y^2+z^2}},\dfrac {z} {\sqrt{x^2+y^2+z^2}} \right \}$

    Take the divergence and then take the gradient and plow through the algebra. It's not that bad. You end up with the right hand side when you're done.
    so is it,

     \frac{\partial}{\partial x }( \{ \dfrac {x} {\sqrt{x^2+y^2+z^2}}) + \frac{\partial}{\partial y }  \dfrac {y} {\sqrt{x^2+y^2+z^2}}, + \frac{\partial}{\partial z}\dfrac {z} {\sqrt{x^2+y^2+z^2}}

    than use the quotient rule for each one?
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  4. #4
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    Re: gradient operator

    Quote Originally Posted by Tweety View Post
    so is it,

     \frac{\partial}{\partial x }( \{ \dfrac {x} {\sqrt{x^2+y^2+z^2}}) + \frac{\partial}{\partial y }  \dfrac {y} {\sqrt{x^2+y^2+z^2}}, + \frac{\partial}{\partial z}\dfrac {z} {\sqrt{x^2+y^2+z^2}}
    if you move the delx operator inside those braces, then what you have there is the div operator. Once you find that you'll have a scalar function in 3 variables, (x, y, z). Take the gradient of that function, simplify it, substitute r in where appropriate and you'll end up with the answer.
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  5. #5
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    Re: gradient operator

    Quote Originally Posted by Tweety View Post
    so is it,

     \frac{\partial}{\partial x }( \{ \dfrac {x} {\sqrt{x^2+y^2+z^2}}) + \frac{\partial}{\partial y }  \dfrac {y} {\sqrt{x^2+y^2+z^2}}, + \frac{\partial}{\partial z}\dfrac {z} {\sqrt{x^2+y^2+z^2}}

    than use the quotient rule for each one?
    You might find it simpler to write x(x^2+ y^2+ z^2)^{-1/2}, etc. and use the product rule.
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  6. #6
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    Re: gradient operator

    I worked it out using the quotient rule
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