Hi everyone,
Could someone please tell me if this is correct?
Find the numbers b such that the average value of f(x)=2+6x-3x^2 on the interval [0, b] is equal to 3.
int. o to b 2+6x-3x^2
2x+6x^2/2-3x^3/3 from 0 to b=
2x+3x^2-x^3 from 0 to b=
2b+3b^2-b^3=3
b(2+3b-b^2)=3
2+3b-b^2=3
-1+3b-b^2=0
-b^2+3b-1=0
b=3
b=.382
b=2.618
Therefore, b=2.618
Thank you very much