Hi everyone,

Could someone please tell me if this is correct?

Find the numbers b such that the average value of f(x)=2+6x-3x^2 on the interval [0, b] is equal to 3.

int. o to b 2+6x-3x^2

2x+6x^2/2-3x^3/3 from 0 to b=

2x+3x^2-x^3 from 0 to b=

2b+3b^2-b^3=3

b(2+3b-b^2)=3

2+3b-b^2=3

-1+3b-b^2=0

-b^2+3b-1=0

b=3

b=.382

b=2.618

Therefore, b=2.618

Thank you very much