The graph of a derivative f '(x) is shown in Figure 5.61.Figure 5.61. Graph of f', not fFill in the table of values for f(x) given that f(0) = 5.
x0123456f(x)5
can someone get me started please...it would really help..thanks....
we can see from the given graph that:
f '(x) = -x_____0 <= x <= 1
______-1 _____1 <= x <= 3
______x-4_____3 <= x <= 5
_______1______5 <= x <= 6
let's integrate f '(x) in the first interval:
f(x) = integ(-x dx) = -x^2 / 2 + C for all 0 <= x <= 1
now we know that f(0) = 5, thus C = 5
---> f(x) = 5 - 0.5*x^2 0<= x <= 1
which means that f(1) = 4.5
now we proceed to integrate f '(x) in the following interval using the initial condition you've got from the previous interval namely f(1) = 4.5, we continue this way till the last interval...