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Math Help - Please Help!! Calculus 1 question!

  1. #1
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    Please Help!! Calculus 1 question!

    Hi,

    I'm a bit confused about this implicit differentiation question.

    Find the equation of the tangent to the curve 2x2 + y - xy2 - 2y3 = 4 at the point (-1, -1).

    I am confused because substituting the x and y coordinates into the above equation does not equal to 4. Does this simply mean that the line is not on the curve?

    I solved for dy/dx and got (-4x - y2) / (1-x2y-6y3) and substituting (-1, -1) into this equation I got the slope of the tangent to the curve to be y= 1/3 (x+1) -1.

    Does this seem right?

    Please Help?!

    Thank you
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  2. #2
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    Re: Please Help!! Calculus 1 question!

    Quote Originally Posted by soniadso View Post
    Hi,

    I'm a bit confused about this implicit differentiation question.

    Find the equation of the tangent to the curve 2x2 + y - xy2 - 2y3 = 4 at the point (-1, -1).

    I am confused because substituting the x and y coordinates into the above equation does not equal to 4. Does this simply mean that the line is not on the curve?

    I solved for dy/dx and got (-4x - y2) / (1-x2y-6y3) and substituting (-1, -1) into this equation I got the slope of the tangent to the curve to be y= 1/3 (x+1) -1.

    Does this seem right?

    Please Help?!

    Thank you
    check your math. (-1,-1) is on that curve.

    your derivative isn't quite correct but it's close enough that I believe you have the right idea. Check your algebra and differentiation.

    Once you have the proper derivative formula just evaluate it at (-1,-1) to get a value for the slope at that point.

    Then with the point (-1,-1) and the slope you can produce the equation for the tangent line using point slope form.
    Thanks from soniadso
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  3. #3
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    Re: Please Help!! Calculus 1 question!

    Thank you for your reply !!

    I rechecked the equation and got dy/dx = (-4x-y2) / (1-x2y-6x2)

    and the equation of the line to be y = -3/7(x+1)-1 ?
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