Results 1 to 3 of 3

Math Help - average value of a funtion

  1. #1
    Member
    Joined
    Aug 2007
    Posts
    148

    average value of a funtion

    Hi everyone,

    Could you please tell me if this is correct?

    Find the average value of the function on the given interval

    g(x)=x^2sq.(1+x^3) [0,2]

    1/2int. [1/3sq. u]du=
    u^3/2/(9)=

    .314

    Thank you very much
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    average value = (Gb -Ga) / (b -a)

    g(x) = (x^2)sqrt(1 +x^3), [0,2]

    (Gb -Ga) = INT.(0-->2)[(1 +x^3)^(1/2)](x^2 dx)
    = INT.(0-->2)[(1 +x^3)^(1/2)](x^2 dx)(3/3)
    = (1/3)[(2/3)(1 +x^3)^(3/2)]|(0-->2)
    = (2/9)[(1 +2^3)^(3/2) -(1 +0^3)^(3/2)]
    = (2/9)[(9)^(3/2) -(1)^(3/2)]
    = (2/9)[27 -1]
    = 52/9

    (b -a) = 2 -0 = 2

    So, average value is (52/9) /2 = 26/9 = 2.889 -------answer.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Aug 2007
    Posts
    148
    Thank you very much
    Last edited by chocolatelover; November 16th 2007 at 12:33 PM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 5
    Last Post: May 26th 2011, 05:11 AM
  2. Replies: 2
    Last Post: March 13th 2010, 04:49 AM
  3. a differential funtion
    Posted in the Differential Geometry Forum
    Replies: 7
    Last Post: August 12th 2009, 11:58 AM
  4. Funtion bessel
    Posted in the Calculus Forum
    Replies: 4
    Last Post: April 2nd 2008, 07:01 AM
  5. Polynomial Funtion HELP PLEASE!!!
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: October 13th 2007, 01:11 PM

Search Tags


/mathhelpforum @mathhelpforum