v(t) = dD/dt = 20t/9
200*1000/3600 = 20t/9
t = 25 seconds
it takes 25 second before airborne
the distance = 10(625)/9= 694,444444 meters
Suppose that the distance an aircraft travels along a runway befoer takeoff is given by , where D is measured in meters from the starting point and t is measured in seconds from that time the brakes are released If the airplane will become airborne when its speed reaches 200 km/h, how long will it take to become airborne, and what distance will it have traveled by that time?
Okay, I think
1st find velocity (derivative of distance)
Then solve for t. T= 90 h
2nd plug 90 for t in the original equation.
and solve for t.
t= 9000 km/h
Yes? NO? Maybe so?