Solve by using Undetermined Coefficients:
y''+y=e^x+x^3 , y(0) = 2 , y'(0) = 0
so I found r to equal + i which gives the first particular solution
y(x) = C1*cosx+C2sinx
for the first side I got yp(x) = Ae^x and both y' and y'' to equal Ae^x.
I solved for A to get 1/2.
can someone show me the 2nd part with the x^3? what would my yp(x) be? thanks