Re: Limit of a complex function with cubed conjugate
Originally Posted by Phyba
So that means that arg(z) doesn't go to zero when z goes to zero, right? (I meant to say both theta and r earlier, I'm sorry)
in this case no. You can contrive things so both the modulus and the argument go to zero but in this case only the modulus does. Note that speaking of the argument of 0 is nonsensical as it can be any value.