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Thread: Hyberbolic function

  1. #1
    Apr 2014

    Hyberbolic function

    Hello attached is the question part C which I need help on and my working out so far for part c. I was wondering if I was going about it right and if anyone could give some clues or advice it would be much appreciated.

    Kind regards
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  2. #2
    MHF Contributor
    Mar 2010

    Re: Hyberbolic function

    In your solution to (b), you should have noticed that the "-2" could have been any number. So when you substitute $\displaystyle x=ct$, you want the ratio of the coefficient of $\displaystyle t^3$ to the coefficient of $\displaystyle t$ to be 4 to 3 - use that to find c. Then you can multiply the whole equation by something to get $\displaystyle 4t^3 + 3t + \text{whatever} = 0$. Then you just make the substitution and solve the equation like you did in (b).

    - Hollywood
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