How would I find the second-degree Taylor series for $\displaystyle x^2+y^2=4 $ at $\displaystyle [1, -\sqrt[]{3}]$?
Follow Math Help Forum on Facebook and Google+
Originally Posted by Anewk How would I find the second-degree Taylor series for $\displaystyle x^2+y^2=4 $ at $\displaystyle [1, -\sqrt[]{3}]$? note that given the point they want you to expand about, $(1,-\sqrt{3})$ you can write $y(x)=-\sqrt{4-x^2}$ and just take the first couple of derivatives and evaluate at $x=1$ and plug into your taylor series formula.
View Tag Cloud