stuck with this one
solve for x: 16^x-5*8^x=0
Or for log to any base, x log(16)= log(5)+ x log(8) so x(log(16)- log(8))= x(log(16/8))= x(log(2))= log(5) and x= log(5)/log(2).
Another way to do this is, since [tex]8^x[/itex] is never 0, to divide both sides by :
and then so