Taylor Expansion....

**Got5onIt** · November 13th 2007, 07:55 PM

Find the Taylor Expansion:

$f(x)=3x^3+2x^2+x+1$ as a polynomial in $x-1$ so $a =1$

I'm not exactly sure what the question is asking me to do with the $x-1$ , throwing me for a loop. I know how to find the expansion if we're only looking at $a=1$ . The $x-1$ is confusing the hell out of me.

Any help is greatly appreciated!!

**ThePerfectHacker** · November 13th 2007, 08:03 PM

Just find the Taylor series for $f(x)$ centered at $1$ .

**Got5onIt** · November 13th 2007, 08:19 PM

Originally Posted by ThePerfectHacker

Just find the Taylor series for $f(x)$ centered at $1$ .

Find the series using x=1?

**ThePerfectHacker** · November 13th 2007, 08:20 PM

You need to pay more attention in class, and read the book.

The Taylor series cented at one would be,
$f(1)+\frac{f'(1)(x-1)}{1!}+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}+...$ .

You should be able to do that.

**Got5onIt** · November 13th 2007, 08:23 PM

Originally Posted by ThePerfectHacker

You need to pay more attention in class, and read the book.

The Taylor series cented at one would be,
$f(1)+\frac{f'(1)(x-1)}{1!}+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}+...$ .

You should be able to do that.

Well, yeah I know how to do that. I have spent the last hour reading the 2 chapters on Taylor expansions. However, nowhere in the book does it give a question worded the way I originally posted in the topic. This was a problem created by my professor at the end of the last class. The wording (x-1) confused me.

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