# Taylor Expansion....

• Nov 13th 2007, 08:55 PM
Got5onIt
Taylor Expansion....
Find the Taylor Expansion:

$f(x)=3x^3+2x^2+x+1$ as a polynomial in $x-1$ so $a =1$

I'm not exactly sure what the question is asking me to do with the $x-1$, throwing me for a loop. I know how to find the expansion if we're only looking at $a=1$. The $x-1$ is confusing the hell out of me.

Any help is greatly appreciated!!
• Nov 13th 2007, 09:03 PM
ThePerfectHacker
Just find the Taylor series for $f(x)$ centered at $1$.
• Nov 13th 2007, 09:19 PM
Got5onIt
Quote:

Originally Posted by ThePerfectHacker
Just find the Taylor series for $f(x)$ centered at $1$.

Find the series using x=1?
• Nov 13th 2007, 09:20 PM
ThePerfectHacker
You need to pay more attention in class, and read the book.

The Taylor series cented at one would be,
$f(1)+\frac{f'(1)(x-1)}{1!}+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}+...$.

You should be able to do that.
• Nov 13th 2007, 09:23 PM
Got5onIt
Quote:

Originally Posted by ThePerfectHacker
You need to pay more attention in class, and read the book.

The Taylor series cented at one would be,
$f(1)+\frac{f'(1)(x-1)}{1!}+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}+...$.

You should be able to do that.

Well, yeah I know how to do that. I have spent the last hour reading the 2 chapters on Taylor expansions. However, nowhere in the book does it give a question worded the way I originally posted in the topic. This was a problem created by my professor at the end of the last class. The wording (x-1) confused me.:o