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Math Help - integration help

  1. #1
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    integration help

    can i do integration of a function in x with respect to t range of t in terms of x and x range not given
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  2. #2
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    Re: integration help

    you'll have to rephrase this one. I have no idea what you're asking.
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  3. #3
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    Re: integration help

    i mean

    integration help-codecogseqn.gif
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  4. #4
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    Re: integration help

    Quote Originally Posted by prasum View Post
    i mean

    Click image for larger version. 

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    you can. I doubt it's what you're after

    $\displaystyle{\int_0^x}e^{-x^2}~dt=e^{-x^2}\displaystyle{\int_0^x}~dt=e^{-x^2}t \left |_0^x\right.=xe^{-x^2}$
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  5. #5
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    Re: integration help

    yeah this only
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  6. #6
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    Re: integration help

    if i want to solve the value for x for which the above integral is 0 what should it be
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  7. #7
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    Re: integration help

    Quote Originally Posted by prasum View Post
    if i want to solve the value for x for which the above integral is 0 what should it be
    $x e^{-x^2}=0$

    $e^{-x^2} > 0~~\forall x \in \mathbb{R} \Rightarrow \\ \\

    x e^{-x^2}=0\Rightarrow x=0$
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  8. #8
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    Re: integration help

    if the integral is e^(-x^2) dx from 0 to x and if this integral is 0 what will be the value of x from newton raphsons method
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  9. #9
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    Re: integration help

    Quote Originally Posted by prasum View Post
    if the integral is e^(-x^2) dx from 0 to x and if this integral is 0 what will be the value of x from newton raphsons method
    this is a completely different problem. Now you are integrating with respect to x, not t. If you are integrating with respect to x it makes no sense to have x as a limit of integration.

    What I believe you mean is

    $\displaystyle{\int_0^x}e^{-t^2}~dt$

    is this correct?
    Thanks from prasum
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  10. #10
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    Re: integration help

    why cant e^(-x^2) dx with limit x come
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  11. #11
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    Re: integration help

    Quote Originally Posted by prasum View Post
    why cant e^(-x^2) dx with limit x come
    You have two different x's, so it's bound to confuse someone - most likely yourself.

    - Hollywood
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