I have been given this question

The Archimedean spiral is given by the polar equation

r= C(theta) where C is a constant.

Find the area when theta is between 0 and 2pi?

Does this mean that i just use the area of a circle equation A= pi r^{2}

So the area will be pi(2pi^{2})-pi(0)= pi(2pi^{2})