Hello, everyone. I am new here. This is just high school Calculus. Don't laugh at me .
Can someone tell me how these problems work? I even looked at the answers (yes, I *am* allowed to do that) but I can't work them backwards. The first one is this:
dy/dx = y+2
And this is what I did:
dy = (y+2) dx
y = Ce^x + 2x
Now the answer is y = Ce^x - 2 .
And the second one: y' = y√x
And last: (1 + x^2)y' = 2xy