The position function s of a point P moving on a coordinate line l is given, with t in seconds and s(t) in centimeters.

(a) Find the average velocity of P in the following interval [1, 1.2].

(b) Find the velocity of P at t = 1.

s(t) = 4t^2 + 3t

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- Mar 5th 2014, 01:30 PMjoshuaaFind the Average Velocity
The position function s of a point P moving on a coordinate line l is given, with t in seconds and s(t) in centimeters.

(a) Find the average velocity of P in the following interval [1, 1.2].

(b) Find the velocity of P at t = 1.

s(t) = 4t^2 + 3t - Mar 5th 2014, 01:55 PMebainesRe: Find the Average Velocity
a) Average velocity is . So determine and divide by seconds.

b) Given the position function s(t), the velocity equations is . Evaluate for t=1.0. - Mar 5th 2014, 02:27 PMjoshuaaRe: Find the Average Velocity
a) I got average velocity = 11.8

b) I am confused to do it. - Mar 6th 2014, 05:49 AMebainesRe: Find the Average Velocity
Good!

The velocity of the particle at t=1 is equal to the slope of the s(t) curve at t=1. I suggested calculating the derivative to find that slope - have you taken any calculus classes where you have learned about derivatives? If not, then you could plot the graph of s=4^2+3t and use a straight edge to estimate its slope at t=1. Alternatively, you could use the same approach as in part (a) to find the average velocity between two points that are very close to t=1; for example if you calculate the average velocity over the interval t= (0.99, 1.01) you will get a very good approximation of the actual velocity at t=1. - Mar 8th 2014, 04:17 AMjoshuaaRe: Find the Average Velocity
Thank you ebaines for the detailed explanation. Yes, I know how to find the slope using the Derivative.

When I find the derivative of 4t^2 + 3t, I get 8t + 3.

If my calculations went correctly, the Velocity at t = 1, might be 8(1) + 3 = 11. - Mar 8th 2014, 06:56 AMebainesRe: Find the Average Velocity
Correct!