f(x) = 3xe^{-8x}, 0 ≤ x ≤ 2 I don't know how to find the absolute maximum and minimum values. Could you show an example of how to do so, step-by-step, for this question (or a similar one)?
Follow Math Help Forum on Facebook and Google+
get the first derivative and set it equal to zero .search for the solution wich is 1/8 there is the max.....the other min is 0. see the attached graph
Originally Posted by angie427 f(x) = 3xe^{-8x}, 0 ≤ x ≤ 2 I don't know how to find the absolute maximum and minimum values. Could you show an example of how to do so, step-by-step, for this question (or a similar one)? I am not sure that I understand your question. Are you asking about the difference between global and local extrema?
Originally Posted by MINOANMAN get the first derivative and set it equal to zero .search for the solution wich is 1/8 there is the max.....the other min is 0. see the attached graph You shouldn't need the graph. In general, in addition to f'=0, you need to ck end points.
Ok thank you everyone for your help.
View Tag Cloud