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Math Help - error bounds

  1. #1
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    error bounds

    Is it the the maximum on the closed interval [a,b] not the largest local maximum, correct? (unless that largest local maximum is also the largest value on the closed interval)

    and what if the function ends up having a vertical asymptote on the interval? such has 6/x on [0,3]
    Last edited by Jonroberts74; February 18th 2014 at 07:12 PM.
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  2. #2
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    Re: error bounds

    Quote Originally Posted by Jonroberts74 View Post
    Another quick question about error bounds.
    Pretty sure that both of us just plotted f'' and eyeballed that the maximum was at x=0 but more formally

    if you had taken the 3rd derivative you would find that it is non-zero on [0,3].

    Thus the maximum has to be at a boundary point of your interval.

    Clearly |f''(3)| < |f''(0)| so f''(0) must be the maxima on [0,3]


    most likely a vertical asymptote within your limits of integration mean that your function isn't integrable on this interval.
    Last edited by romsek; February 18th 2014 at 07:22 PM.
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  3. #3
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    Re: error bounds

    this is for k_{4} which is the fourth derivative is what I am looking at now the fourth derivative gives me 6/x. so how can I find the error bounds if I cant put a maximum on that interval?
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