okay so the integral is $\displaystyle \int_{0}^{3} \sqrt{x+1}dx$ and using midpoint approximation so I use

$\displaystyle \frac{(b-a)^3k_{2}}{24n^2}, where\,n=10\,and\,k_{2} = max_{[a,b]} |f"(x)|$

$\displaystyle f"(x) = -\frac{1}{4}(x+1)^{-3/2} $ found $\displaystyle k_{2} = \frac{1}{32}$

I am getting $\displaystyle \frac{9}{25600}$ book says 9/3200

also, latex sure is being a pain on here lately