okay so the integral is and using midpoint approximation so I use

found

I am getting book says 9/3200

also, latex sure is being a pain on here lately

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- February 16th 2014, 10:49 PMJonroberts74upper bounds numerical integration error
okay so the integral is and using midpoint approximation so I use

found

I am getting book says 9/3200

also, latex sure is being a pain on here lately - February 17th 2014, 04:21 PMJonroberts74Re: upper bounds numerical integration error
The question then goes on to ask for the upper bounds from trapezoid and simpsons rule but the book has different answers then I am getting. Did I do the first one correctly?

- February 17th 2014, 04:56 PMJonroberts74Re: upper bounds numerical integration error
now the question asks to find the number n of subintervals that will make the error less than

just typing out the midpoint because the book is giving not the same answer I am giving

I am getting n= 9 book is saying n = 24 - February 17th 2014, 11:13 PMromsekRe: upper bounds numerical integration error
I'd like to help you out Jon but w/o a reference to what you're doing I'm not able to figure out what you need figured out.

Is there some online reference that uses the same notation and method? - February 18th 2014, 01:23 AMBobPRe: upper bounds numerical integration error
isn't it ? (Max at

- February 18th 2014, 01:06 PMJonroberts74Re: upper bounds numerical integration error
- February 18th 2014, 01:09 PMJonroberts74Re: upper bounds numerical integration error
- February 18th 2014, 01:43 PMromsekRe: upper bounds numerical integration error
re your first post on this thread

BobP is correct. The max of the absolute value of the 2nd derivative is 1/4 at x=0 which leads to the bound of 9/3200

your 2nd problem is wrong for the same reason. The max value is 1/4 not 1/32 - February 18th 2014, 02:01 PMSlipEternalRe: upper bounds numerical integration error
To reiterate what romsek and BobP are saying:

You are taking , which is the absolute value of the maximum of the second derivative on the given interval. BobP and romsek are saying, take the absolute value function first: . Then, find the maximum. Hence, . - February 18th 2014, 02:12 PMromsekRe: upper bounds numerical integration error
- February 18th 2014, 03:52 PMJonroberts74Re: upper bounds numerical integration error
I see how I was messing up, taking the absolute of the answer not of the function. thanks