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Math Help - Vector parametric equation

  1. #1
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    Vector parametric equation

    Hey everyone, i just had a question that for some reason i can't figure out
    The question is:

    Give a vector parametric equation for the line through the point (-5,-2) that is perpendicular to the line <-2,-4-4t>.

    I'm really confused because i tried to found the vector v = <0,-4> and then did the dot product as (x,y) . (0,-4) = 0. i get x = 0 and y = 0
    can someone help me

    thanks alot
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  2. #2
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    Re: Vector parametric equation

    This question is deceptively simple. If the normal line is t(0, -4) + (-2, -4), then that means x = -2 and y = -4t - 4. In other words, no matter what value you plug in for t, the x value does not change. What does that tell you about the normal line? What does that tell you about the line you are trying to find?
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