Consider them as one fraction: .
Using synthetic division, i factored the denominator: . . . . . Good!
After the partial fractions technique: . . . . . Yes!
i had: . . . . . Right!
i figured out the 1st part using the ln antiderivative.
But i cant figure out how to integrate the 2nd, 3rd terms.
Now we'll perform some Olympic-level gymnastics on the numerator.
We have: .
Factor out -23: .
And we have: .
The integral becomes: .
The last denominator is: .
And the last integral is: . . . . arctangent form!
I need a nap!