Say I have a limit that, on a first direct evaluation, gives (0 x infinity)/0. Can I still use L'Hospitals rule? The specific limit I've been given is (x^2(sin(1/x)))/sinx as x approaches 0. It seems that I could divide the numerator by 1/sin(1/x)), which would give 0/0/0 which doesn't seem to help. Is it even possible?