What is the area of the region between the graphs of y=x^2 and y = .x from x= 0 to x = 2?
a. (2/3)
b. (8/3)
c. 4
d. (14/3)
e. (16/3)
Hello,Originally Posted by frozenflames
as you may have noticed, the 2nd equation is damaged slightly. By the given borders (0 and 2) I guessed, that this equation should be linear and that the intercepting point between parabola and straight line should be (2,4). Therefore I guess that the 2nd equation should be y=2*x. If not, all following calculations are wrong!
You calculate the enclosed area as integral of the difference of functions, from one intercepting point to the next one.
The difference is here: and the intercepting points are (0,0) and (2,4).
The area is
This answer is missing in your list of possible answers, so my assumption about the 2nd equation must be wrong. Sorry that I couldn't help you.
Greetings
EB