You forgot to mention the limits of integration, which I think are 0 to .
You use the reduction formula twice to get = some number times . Then can be integrated by substituting .
- Hollywood
Okay, so I have this reduction formulae question
Establish a reduction formula to find I_{m,n} =∫cos ^{m} x . sin ^{n} x dx
Prove that (m+n). I_{m,n} = (m-1) . I_{m-2,n }And okay I solve the problem above, but then the question says
evaluate I_{5,6 }and I can't find the value 8/693 which is the answer in answer key. I'm so confused, what I need to do is just substituting the value right?
But the problem is the I is the integral of ∫cos ^{m} x . sin ^{n} x dx so what to do with x, do we just put whatever on x, or what?
Please help me ! thanks