I'm not sure how to go about solving this problem, so any help will be much appreciated! v'= 3 times the radical of t v(1)= 3 v(4)= ?
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Originally Posted by blurain I'm not sure how to go about solving this problem, so any help will be much appreciated! v'= 3 times the radical of t v(1)= 3 v(4)= ? $\displaystyle v^{\prime} = 3\sqrt{t}$ So $\displaystyle \int v^{\prime}~dt = \int 3 \sqrt{t}~dt$ $\displaystyle v(t) = 3 \cdot \frac{1}{\frac{3}{2}}t^{3/2} + C = 2\sqrt{t^3} + C$ Now use v(1) = 3 to find the value for C. -Dan
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