If dy/dt = ky and k is a nonzero constant, then y could be a. 2e^kry b. 2e^kt c. e^kt +3 d. kty + 5 e. (1/2)ky^2 + (1/2)
Follow Math Help Forum on Facebook and Google+
Originally Posted by frozenflames If dy/dt = ky and k is a nonzero constant, then y could be a. 2e^kry b. 2e^kt c. e^kt +3 d. kty + 5 e. (1/2)ky^2 + (1/2) All solutions to this diffrencial equation are, Notice that #2: works because . The easiest way is to check which one makes the differencial equation true.
View Tag Cloud