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Math Help - Derivative Question

  1. #1
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    Derivative Question

    If dy/dt = ky and k is a nonzero constant, then y could be

    a. 2e^kry
    b. 2e^kt
    c. e^kt +3
    d. kty + 5
    e. (1/2)ky^2 + (1/2)
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  2. #2
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    Quote Originally Posted by frozenflames
    If dy/dt = ky and k is a nonzero constant, then y could be

    a. 2e^kry
    b. 2e^kt
    c. e^kt +3
    d. kty + 5
    e. (1/2)ky^2 + (1/2)
    All solutions to this diffrencial equation are,
    y=Ce^{kt}

    Notice that #2:
    2e^{kt} works because C=2. The easiest way is to check which one makes the differencial equation true.
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