If dy/dt = ky and k is a nonzero constant, then y could be

a. 2e^kry

b. 2e^kt

c. e^kt +3

d. kty + 5

e. (1/2)ky^2 + (1/2)

Printable View

- March 18th 2006, 01:09 PMfrozenflamesDerivative Question
If dy/dt = ky and k is a nonzero constant, then y could be

a. 2e^kry

b. 2e^kt

c. e^kt +3

d. kty + 5

e. (1/2)ky^2 + (1/2) - March 18th 2006, 04:25 PMThePerfectHackerQuote:

Originally Posted by**frozenflames**

Notice that #2:

works because . The easiest way is to check which one makes the differencial equation true.