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you have the integral sqrt(1+sin(x)^2) from 0 to 2π.( π=3,14...)

Quote: Originally Posted by bembas you have the integral sqrt(1+sin(x)^2) from 0 to 2π.( π=3,14...) The answer appears to be in the form of a Complete Elliptic integral of the second kind. Are you sure you have the right formula?