1. Originally Posted by Prophet
So, then you take the derivative of this function and then set it equal to 0, I took the derivative and got that function... but I was just wondering if my differentiation was correct.
it isn't correct. you would need the chain rule, which you didn't use

2. Originally Posted by Jhevon
it isn't correct. you would need the chain rule, which you didn't use
I did it again and got 2~3^(1/2) - 4x - (16-x^2)^(-1/2) = D'

~ = times

3. Originally Posted by Prophet
I did it again and got 2~3^(1/2) - 4x - (16-x^2)^(-1/2) = D'

~ = times

Correct that, -2~3^1/2 - (16-x^2)^(-1/2)

4. $D = (\sqrt{3} - x)^2 + \left(1 - \sqrt{16 - x^2} \right)^2$

$\Rightarrow D' = -2(\sqrt{3} - x) -\frac {2x \left( 1 - \sqrt{16 - x^2} \right)}{\sqrt{16 - x^2}}$

now simplify

5. Does the F^2 have anything to do with the final result at all?

6. I set that equation equal to 0 and got x = 3^(1/2) and :P 2~3^(1/2)= (-)[1+(16-x^2)^(1/2)]/(16-x^2)^(1/2) do you know how to simplify that :P?

7. And for number 3.
$S=k(144w-w^{3})
$

When we differentiate that, do we have to use implicit differentiation... since there is a k and a w involved, or do we leave out the k because the type of wood isn't required?

8. Originally Posted by Prophet
And for number 3.
$S=k(144w-w^{3})
$

When we differentiate that, do we have to use implicit differentiation... since there is a k and a w involved, or do we leave out the k because the type of wood isn't required?
k is a constant, it is the constant of proportionality

9. Oh okay, I understand, so we can just move it out of the differential, I see thanks.

10. Originally Posted by Prophet
Does the F^2 have anything to do with the final result at all?
no, we are just maximizing the square of the distance, it is the same as maximizing the distance itself

Page 2 of 2 First 12