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**Deadstar** I have a question on a tutorial involving using the $\displaystyle \epsilon - \delta$ definition to prove a function is continuous. I missed the lectures on this so im not sure about it...

Let $\displaystyle f(y) = \sqrt[3] {y +3}$ and b > -3

Prove, from the $\displaystyle \epsilon - \delta$ definition, that f(y) is continuous at y = b.

[hint use the identity $\displaystyle u^3 - v^3 = (u - v)(u^2 + uv + v^2)$]

Prove, from the $\displaystyle \epsilon - \delta$ definition, that f(y) is continuous from the right at y = -3

any help appreciated.