Help In Calculus Needed

**frozenflames** · March 18th 2006, 12:02 PM

see attached

**earboth** · March 18th 2006, 10:39 PM

Originally Posted by frozenflames

see attached

Hello,

you have to find $\int {sin(x) \cdot cos(y)\ dx$

Substitute $u=sin(x)\ \Longrightarrow \ \frac{du}{dx}=cos(x)\ \Longrightarrow \ du=cos(x) \cdot dx$

The integral is now $\int {u \cdot du}=\frac{1}{2}(u)^2+c$

Re-substitute and you'll get: $\int {sin(x) \cdot cos(y)\ dx=\frac{1}{2}(sin(x))^2+c$

So it is answer A.

Greetings

EB

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