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Math Help - Help In Calculus Needed

  1. #1
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    Help In Calculus Needed

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  2. #2
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    Quote Originally Posted by frozenflames
    see attached
    Hello,

    you have to find \int {sin(x) \cdot cos(y)\ dx

    Substitute u=sin(x)\ \Longrightarrow \ \frac{du}{dx}=cos(x)\ \Longrightarrow \ du=cos(x) \cdot dx

    The integral is now \int {u \cdot  du}=\frac{1}{2}(u)^2+c

    Re-substitute and you'll get: \int {sin(x) \cdot cos(y)\ dx=\frac{1}{2}(sin(x))^2+c

    So it is answer A.

    Greetings

    EB
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