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Math Help - Trying to find the Limit using L'hospital's rule. My work is shown in the image. plea

  1. #1
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    Trying to find the Limit using L'hospital's rule. My work is shown in the image. plea

    Trying to find the Limit using L'hospital's rule. My work is shown in the image. plea-mywork1.png
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  2. #2
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    Re: Trying to find the Limit using L'hospital's rule. My work is shown in the image.

    Take the derivative of the numerator again. Remember to use the Chain Rule for the second term.
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    Re: Trying to find the Limit using L'hospital's rule. My work is shown in the image.

    ahhh I figured it out, I was calculating -e^-0 as -1, when really it is 1.
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  4. #4
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    Re: Trying to find the Limit using L'hospital's rule. My work is shown in the image.

    Actually, -e^{-0} = -e^0 = -1. You had that part correct. Your derivative was not correct: \dfrac{d}{dx}(e^x - e^{-x}) = e^x + e^{-x}
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