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Math Help - Calculus Problem!!!!

  1. #1
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    Calculus Problem!!!!

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  2. #2
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    Quote Originally Posted by frozenflames
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    Hello,

    first you have to calculate the radius of the rotation, which is here the x-coordinate of every point of the curve:
    y=\sqrt{x}\ \Longrightarrow \ x=y^2

    in general the volume of a rotating curve is calculated as
    V=\pi \cdot \int{r^2\ dy}

    Then V=\int^{2}_{0}{\pi \cdot (y^2)^2 dy=\pi \cdot \left[\frac{1}{5} y^5 \right]^{2}_{0}

    So the right answer is A: \frac{32}{5} \pi

    Greetings

    EB
    Last edited by earboth; March 19th 2006 at 12:35 AM.
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