# Calculus Problem!!!!

• March 18th 2006, 11:59 AM
frozenflames
Calculus Problem!!!!
• March 18th 2006, 10:10 PM
earboth
Quote:

Originally Posted by frozenflames

Hello,

first you have to calculate the radius of the rotation, which is here the x-coordinate of every point of the curve:
$y=\sqrt{x}\ \Longrightarrow \ x=y^2$

in general the volume of a rotating curve is calculated as
$V=\pi \cdot \int{r^2\ dy}$

Then $V=\int^{2}_{0}{\pi \cdot (y^2)^2 dy=\pi \cdot \left[\frac{1}{5} y^5 \right]^{2}_{0}$

So the right answer is A: $\frac{32}{5} \pi$

Greetings

EB