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- Mar 18th 2006, 11:59 AMfrozenflamesCalculus Problem!!!!
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- Mar 18th 2006, 10:10 PMearbothQuote:

Originally Posted by**frozenflames**

first you have to calculate the radius of the rotation, which is here the x-coordinate of every point of the curve:

$\displaystyle y=\sqrt{x}\ \Longrightarrow \ x=y^2$

in general the volume of a rotating curve is calculated as

$\displaystyle V=\pi \cdot \int{r^2\ dy}$

Then $\displaystyle V=\int^{2}_{0}{\pi \cdot (y^2)^2 dy=\pi \cdot \left[\frac{1}{5} y^5 \right]^{2}_{0}$

So the right answer is A: $\displaystyle \frac{32}{5} \pi$

Greetings

EB