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- March 18th 2006, 12:54 PMfrozenflamesCalculus Problem
Please See Attached

- March 18th 2006, 04:57 PMThePerfectHacker
You are going to be using the formula

First see that you are taking the integral from until that is when it intersects the x and y axes.

Now you need to find :

Notice that implies .

At the width of the line perpendicular to the x-axis is then . But this is the diameter of the circle. Thus, its radius is .

The area of this cross section (semicircle) is

(remember the 1/2 it is semi-circle :eek: )

Thus,

I think there is something wrong with your choices. - March 18th 2006, 06:42 PMRich B.
Dear PHckr:

Line #5 of your narrative reads:

Notice that http://www.mathhelpforum.com/math-he...db6e2cfd-1.gif implies http://www.mathhelpforum.com/math-he...428afcca-1.gif.

Do you see the problem?

Regards,

Rich B.

- March 19th 2006, 11:24 AMThePerfectHackerQuote:

Originally Posted by**Rich B.**