(5x)Σcos(x) cosu^4 du=

I got 5cos(20x^3)+cos(4cos(x)^3)(sin(x)) but it is incorrect. can someone explain to me why this is incorrect help me correct it?

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- Nov 21st 2013, 05:41 PMrhcprule3FTC part 2 help
(5x)Σcos(x) cosu^4 du=

I got 5cos(20x^3)+cos(4cos(x)^3)(sin(x)) but it is incorrect. can someone explain to me why this is incorrect help me correct it? - Nov 22nd 2013, 03:34 PMchiroRe: FTC part 2 help
Hey rhcprule3.

What does the sigma refer to? Is it a summation and if so, what are the limits and dummy indices? - Nov 22nd 2013, 04:32 PMHallsofIvyRe: FTC part 2 help
With that "du" I'm inclined to believe you mean an integration with respect to u But then what about the "5x" and "cos(x)"? Do you mean, the simplest way I can interpret this,

? To integrate that you could use , twice. But I cannot imagine where you could have got that "20" inside the cosine, much less the cube! So perhaps I am misunderstanding completely.