I picked up a new textbook and this exercise was in it

x u(x) v(x) u'(x) v'(x) 2 -3 4 6 5 3 2 7 -2 1

then it wants me to find $\displaystyle \frac{dy}{dx}$ for $\displaystyle \frac{u(x)}{v(x)}$ for x = 2 and $\displaystyle v(u(x))$ when x = 3

the first one was easy and I got $\displaystyle \frac{39}{16}$

the second one I figured would be easy as well. the book has $\displaystyle -10$ but I got

$\displaystyle dy/dx = v'(u(x)) * u'(x) \Rightarrow (1)(2)(-2)=-4$