Consider the following table: x 0 3 6 9 12 15 f(x) 41 40 38 34 26 9 Use this to estimate the integral: Sigma notation[15 over 0]fxdx=
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Nevermind guys, i figured it out.
Good. $\displaystyle \int_0^{15} f(x)dx$ can be approximated by the Riemann sum (41+ 40+ 38+ 34+ 26+ 9)(15/5)= (41+ 40+ 38+ 34+ 26+ 9)(3).
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