solve the numerator as equation to find the roots of g'(x) =0 then verify where the g'(x) is < 0 or >0 it is easy.
g(x) = 5x-3.8/(5x-14.44)^{2 }I got the derivative: g'(x) = [(25x-72.7)^{2} - (50x-38)]/ (5x-14.44)^{4 }How do you find the intervals for this function?