So the problem indicates:
Suppose y= sin x , for x in [n/2, 3n/2] *note let n=pi
Then we define P to be the inverse of this function.
Ex. P(0) = n
a. Obtain the derivative of P. The derivative is not P'(x) = 1/[(1-x^2)^(1/2)].
So I'm not entirely sure how to go about this.
We can write P(x) =y for x in [-1, 1].
Then I know that on the interval [n/2, 3n/2] the derivative of the sine function will be negative.
But I'm unsure how to approach it?