I am studying the attached image: I find myself wondering is it: $\displaystyle m(a)=\lim \Delta x\rightarrow 0\frac{a^\Delta^x-1}{\Delta x}$ or is it: $\displaystyle m(a)=a^x\lim \Delta x\rightarrow 0\frac{a^\Delta^x-1}{\Delta x}$ Thanks in advance...
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It is the first one.
Why then is it said: $\displaystyle m(a)=\frac{d}{dx}a^x ...at... x=0$ it is confusing me if m(a) is the first one I posted. Clearly before they said: $\displaystyle m(a)=\frac{d}{dx}a^x=m(a)a^x$ Thanks in advance...
OK. That would mean a^x is one at x = 0. I think I get it now.
Exactly.
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