Finding acceleration given velocity

A particle moves along a straight line. When it is a distance s from a fixed point, where s > 1, the velocity v is given by v = (3s + 2) / (2s-1). Find the acceleration when s = 2

When I first did this problem I thought that the answer was simply -7/(2s-1)^2 = -7/9= acceleration

But it turns out you have to use acceleration=dv/dt= dv/ds x ds/dt= v x dv/ds

So the correct answer would just be (-7/9) x (3s+2)/(2s-1), substituting 2 for s?

I would appreciate it if you could tell me if the above method ^^^^ is right or if I need to do something else. Thanks!

Re: Finding acceleration given velocity

Your thought is because the particle is moving along a straight line, $\displaystyle \dfrac{ds}{dt} = v$? That sounds correct to me.

Re: Finding acceleration given velocity

So is the answer to this whole problem -56/27 ?

Re: Finding acceleration given velocity