A Capybara needs to get from point A to point B around a circular pool (see diagram). If the Capybara swims half as fast as he can run, what angle should he jump in the pool to minimize the total travel time?

Attachment 29625

I know that to minimize time traveling you need to find the equation for time then derive and set to zero.

So far I have that time swimming = 2t, time running = t, speed = distance/time

I know that distance traveled on land is r*theta, but I have no idea how to find the distance traveled in water.

Right now my equation is Time spent traveling = r*theta*t + (Distance traveled in water)*2t

How can I find distance traveled by water? And is the rest of what I have done right?