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Math Help - Examining a Curve - # 4

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    Examining a Curve - # 4

    First of all finding the critical numbers is a problem for this one:

    f(x) = 3\sin(x) + 3\cos(x)

    f'(x) = 3\cos(x) + [-3\sin(x)]

    f'(x) = 3\cos(x) - 3\sin(x) Next move, hint?
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    Re: Examining a Curve - # 4

    Quote Originally Posted by Jason76 View Post
    First of all finding the critical numbers is a problem for this one:

    f(x) = 3\sin(x) + 3\cos(x)

    f'(x) = 3\cos(x) + [-3\sin(x)]

    f'(x) = 3\cos(x) - 3\sin(x) Next move, hint?
    Hello,

    I assume that you want to solve for x

     3\cos(x) - 3\sin(x) = 0

    If so:

     3\cos(x) - 3\sin(x) = 0~\implies~1 = \frac{3 \sin(x)}{3 \cos(x)} = \tan(x)

    and therefore:

    x = \tan^{-1}(1)
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