Re: Vector-valued functions

Hey bradyc12.

For Q2 you have to use the parameterization where ds^2 = dx^2 + dy^2 + dz^2. Now divide by dt^2 and take a square root to give you:

(ds/dt) = SQRT((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2).

Remember that the key thing with arc-length is that you finding infinitesimals of pythagoras' theorem where you are adding up the hypotenuses to get the final arc-length.

Re: Vector-valued functions

Cheers Chiro,

Im afraid i already knew that its just when i get past using that formula the integral gets really mess and i cant get a proper answer out of it, any chance you can shine some light on that and q3 please?

Cheers

Re: Vector-valued functions

Can you show us your steps and how far you got?