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Math Help - Having Trouble with simple integration when divsion is involved...

  1. #1
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    Having Trouble with simple integration when divsion is involved...

    S=integration symbol

    S (2/x) dx

    do I move the x to the numerator and make it S(2x^-1) dx

    Then , 2S(x^-1) dx

    But when I do this and integrate it becomes x^0, which isn't working out too well.


    EDIT:
    I think I found what to do,
    If I have
    S(2/x) dx=
    2S(1/x) dx=
    2lnx, with the x being absolute value.

    Am I on the right track?

    Would S (3/x) dx be:

    3S(1/x) dx=
    3 lnx ?

    S(4/x) dx=
    4S(1/x)=
    4lnx?

    and so on?
    Last edited by 2taall; November 9th 2007 at 11:27 AM.
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  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
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    someplace
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    Quote Originally Posted by 2taall View Post
    S=integration symbol

    S (2/x) dx

    do I move the x to the numerator and make it S(2x^-1) dx

    Then , 2S(x^-1) dx

    But when I do this and integrate it becomes x^0, which isn't working out too well.


    EDIT:
    I think I found what to do,
    If I have
    S(2/x) dx=
    2S(1/x) dx=
    2lnx, with the x being absolute value.

    Am I on the right track?

    Would S (3/x) dx be:

    3S(1/x) dx=
    3 lnx ?

    S(4/x) dx=
    4S(1/x)=
    4lnx?

    and so on?
    Yes.

    RonL
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