Thread: Having Trouble with simple integration when divsion is involved...

S=integration symbol

S (2/x) dx

do I move the x to the numerator and make it S(2x^-1) dx

Then , 2S(x^-1) dx

But when I do this and integrate it becomes x^0, which isn't working out too well.


EDIT:
I think I found what to do,
If I have
S(2/x) dx=
2S(1/x) dx=
2lnx, with the x being absolute value.

Am I on the right track?

Would S (3/x) dx be:

3S(1/x) dx=
3 lnx ?

S(4/x) dx=
4S(1/x)=
4lnx?

and so on?

Originally Posted by 2taall

S=integration symbol

S (2/x) dx

do I move the x to the numerator and make it S(2x^-1) dx

Then , 2S(x^-1) dx

But when I do this and integrate it becomes x^0, which isn't working out too well.


EDIT:
I think I found what to do,
If I have
S(2/x) dx=
2S(1/x) dx=
2lnx, with the x being absolute value.

Am I on the right track?

Would S (3/x) dx be:

3S(1/x) dx=
3 lnx ?

S(4/x) dx=
4S(1/x)=
4lnx?

and so on?

Yes.

RonL