Can someone check my work? I've attached it. Thanks!
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It is wrong. Becauase , is some other point in the set. So are all points in the set so that this is true and not .
Originally Posted by ThePerfectHacker It is wrong. Becauase , is some other point in the set. So are all points in the set so that this is true and not . Ok, change all the f(x)'s to y's. Then, I think, it is correct.
TPH, how does it look now? Attached the new one.
Good proof. In the second part where you show is not unfiormly continous, trying using the definition, i.e. show (without Cauchy sequences) that you can violate the definition of uniform continuity.
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