How do i find the dirivative of y=x-1/2x^2.
Thats. y=x - 1 divided by 2x to the power 2.
Any help would be greatful.
Thanks, James.
(where does the math notations everyone seems to use come from? )
We use Latex. (I'll go search for the tutorial and then edit my post and paste it here okay?)
$\displaystyle ( \frac{x - 1}{2x} )^{2}$
$\displaystyle = (x(2x)^{-1} - 1(2x)^{-1})^{2}$
$\displaystyle = \frac{1}{4} - \frac{1}{2} x^{-1} + \frac{1}{4}x^{-2}$
$\displaystyle \frac{dy}{dx} = 0 + \frac{1}{2} x^{-2} - \frac{1}{2}x^{-3}$
$\displaystyle = \frac{1}{2x^2} - \frac{1}{2x^3}$
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EDIT: Krizalid gave you the link